5 kyu
The Dots and Parentheses
69 of 101qpwedev
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is there a way for a possible solution without recursion?
yes. every recursion could be rewrited in loops if language allows loops
Python version: tests for 0 to 11 should be added to sample tests like the other language versions.
someone did
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Can you help me? How to fix it?
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I added new tests, thank you
Ruby translation: https://www.codewars.com/kumite/5fe6342121683a0021e3adee/edit
Haskell translation
Why not a decoder as well as an encoder?
The algorithm for that can be as elegant as for the encoder.
JavaScript translation
This solution usually fails, but sometimes passes all tests. Whether it's correct or not, it should pass of fail consistently.
Fixed, thank you
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IMHO it should be
'((()()).(()))', but I'm not the author.Yes, my bad. Fixed
.
Same as below (open as issue), you need to add random tests.
Can you help me? How can I do random tests?
Random tests are where you give the user 100-200 random natural numbers (between 1-10000). Then you test that they are right. To do so, you check that their answer is the same as your answer for a given natural number.
To generate a random number:
Then create a function as the reference solution:
Now test it:
If you need more help then go to: https://github.com/Codewars/codewars.com/wiki/Codewars-Python-Test-Framework-V2
Thank you
Fixed
You need random tests to prevent hard coded solutions, FYI.