Start a new Kumite
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Kumite (ko͞omiˌtā) is the practice of taking techniques learned from Kata and applying them through the act of freestyle sparring.

You can create a new kumite by providing some initial code and optionally some test cases. From there other warriors can spar with you, by enhancing, refactoring and translating your code. There is no limit to how many warriors you can spar with.

A great use for kumite is to begin an idea for a kata as one. You can collaborate with other code warriors until you have it right, then you can convert it to a kata.

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Code
Diff
  • function getFactors (n) {
      if (!Number.isInteger(n) || n < 1) return [];
      
      var divisors = new Set();  
      for (let i = 1; i <= Math.sqrt(n); i++) {
        if (n % i == 0) divisors.add(i).add(n/i)
      }
      return Array.from(divisors)
    }
    • function getFactors (n) {
    • if (n < 1 || ! Number.isInteger(n)) return [];
    • if (!Number.isInteger(n) || n < 1) return [];
    • let divisors = [];
    • for (let i = 1; i <= Math.sqrt(n); ++i) {
    • if (n % i === 0) {
    • divisors.push(i);
    • if (n / i !== i) divisors.push(n / i);
    • }
    • var divisors = new Set();
    • for (let i = 1; i <= Math.sqrt(n); i++) {
    • if (n % i == 0) divisors.add(i).add(n/i)
    • }
    • return divisors;
    • return Array.from(divisors)
    • }

math.sqrt(n) = n**.5

although that may lead unreadable code.

for python 3 replace long(...) with int(...)

Code
Diff
  • fib = lambda n: long((((1+5**.5)/2)**(n+1) - ((1-5**.5)/2)**(n+1))/5**.5)
    • import math
    • def fib(n):
    • return long((((1+math.sqrt(5))/2)**(n+1) - ((1-math.sqrt(5))/2)**(n+1))/math.sqrt(5))
    • fib = lambda n: long((((1+5**.5)/2)**(n+1) - ((1-5**.5)/2)**(n+1))/5**.5)
Arrays
Data Types
Map/Reduce
Algorithms
Logic
Code
Diff
  • const duplicates = a => a.reduce((r, v, i, l) => !r.includes(v) && l.indexOf(v) !== i ? [...r, v] : r, []);
    • function duplicates(arr) {
    • var out = [];
    • for(var x=0;x<arr.length-1;x++)
    • {
    • var ch = arr[x];
    • for(var y=x+1;y<arr.length;y++)
    • {
    • var comp = arr[y];
    • if (comp === ch && out.indexOf(comp) === -1)
    • {
    • out.push(comp);
    • break;
    • }
    • }
    • }
    • out.sort();
    • return out;
    • }
    • const duplicates = a => a.reduce((r, v, i, l) => !r.includes(v) && l.indexOf(v) !== i ? [...r, v] : r, []);
Code
Diff
  • const middleCharacter = s => s.slice(s.length/2 - !(s.length % 2), s.length/2+1);
    • var middleCharacter = (str) => str.slice(str.length/2 - !(str.length % 2), str.length/2+1);
    • const middleCharacter = s => s.slice(s.length/2 - !(s.length % 2), s.length/2+1);
Code
Diff
  • const convert = n => Number(n.toFixed(2));
    • const convert = (num) => {
    • return parseFloat(num.toFixed(2));
    • };
    • const convert = n => Number(n.toFixed(2));
Code
Diff
  • const greetLanguage = (a = "Hello", b = "Javascript") => `${a}, ${b}!`
    • let greetLanguage = (a = "Hello", b = "Javascript") => `${a}, ${b}!`
    • const greetLanguage = (a = "Hello", b = "Javascript") => `${a}, ${b}!`

Comparing lists using the length function is problematical because it requires counting every item in both lists. However, we only need to count up until the length of the shortest list + 1 to know which one is shorter. This can make a big difference in performance if one list is much longer than the other -- and make the difference between termination and non-termination if one list is infinite.

My change fixes this problem by avoiding the use of the length function. I've also changed the tests to make sure the solution works when one list is infinite.

Code
Diff
  • module CmpStr where
    
    import Data.Function
    import Data.Monoid
    
    cmpStr :: String -> String -> Ordering
    cmpStr = (compare `on` map (const ())) `mappend` compare
    • module CmpStr where
    • import Data.Function
    • import Data.Monoid
    • cmpStr :: String -> String -> Ordering
    • cmpStr = (compare `on` length) `mappend` compare
    • cmpStr = (compare `on` map (const ())) `mappend` compare
Code
Diff
  • def myMap(mine):
        l = [i+1 for i in mine]
        return l
        
    • def sayHello(say):
    • say.append("bulbul")
    • return say
    • def myMap(mine):
    • l = [i+1 for i in mine]
    • return l