Nice

This prob should eat less resources than .toString(), no?

genius

If someone just add 10 more words, this doesn't seem very scalable.

Nice solution

It is a string comparison.

The strings are all like "3:2". So it is "3" > "2" and 3 > 2. String comparison and integer comparison have the same result in this case.

Here the values are all single digits. The method fails if a string is like "12:8" because "12" < "8" and 12 > 8. However, two-digit results are not part of this kata.

Sorry that is not best practices, there is a formular for this problem, which is much more efficient.

We should ban it, it's illegal.

But X and Y would be string, right?, you just can compare them and the compiler knows that it should treat them as integers?

I HATE THIS SOLUTION!!!!!!!!

ITS SO @SS RIGHT?!!!

they deserved it

your solution is this one :|

this solution is so sh!t!!!

this solution is sh!t