Yes
The i for i in is redundant
i for i in
This comment is hidden because it contains spoiler information about the solution
That's why this kata is easy, and this one is not: https://www.codewars.com/kata/621f89cc94d4e3001bb99ef4
lol this is cheating!
No way, this one's quite hard to figure out
Exactly, I missed that. Now I'm stuck with time outsssssss
You didn't read it like you should:
Bash Note: <- This is for Bash only and you used C++ The input strings are separated by , instead of \n. The ouput strings should be separated by \r instead of \n. See "Sample Tests".
Bash Note: <- This is for Bash only and you used C++
The input strings are separated by , instead of \n. The ouput strings should be separated by \r instead of \n. See "Sample Tests".
Maybe that part could be shown only in Bash... but it's clear from the title too.
Very true, this thing is broken.
LMAO Look at the last statement, c < 0. This thing is so wrong yet it passed
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Yes
The
i for i inis redundantThis comment is hidden because it contains spoiler information about the solution
This comment is hidden because it contains spoiler information about the solution
That's why this kata is easy, and this one is not: https://www.codewars.com/kata/621f89cc94d4e3001bb99ef4
lol this is cheating!
No way, this one's quite hard to figure out
Exactly, I missed that. Now I'm stuck with time outsssssss
You didn't read it like you should:
Maybe that part could be shown only in Bash... but it's clear from the title too.
This comment is hidden because it contains spoiler information about the solution
Very true, this thing is broken.
LMAO Look at the last statement, c < 0. This thing is so wrong yet it passed