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SuboX Avatar
Name:Subotic Nikola
Clan:100 Days of Code
Skills:python
Member Since:Dec 2022
Last Seen:Nov 2024
Profiles:
    Following:7
    Followers:7
    Allies:7
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    • Replies (6)
    • Authored
    • Needs Resolution
    • Custom User Avatar
      • brodiemark
      • resolved an issue on "Latin Square Validator" kata
      • 2 years ago

      Mednoob is correct. I'm marking this as resolved.

    • Custom User Avatar
      • Mednoob
      • commented on "Latin Square Validator" kata
      • 2 years ago

      Looking at the tests, I can assure you that it accepts your answers. I think it's because then in your result. It should be than.

    • Custom User Avatar
      • FunkyDck
      • commented on "Growth of a Population" kata
      • 2 years ago

      This comment is hidden because it contains spoiler information about the solution

    • Custom User Avatar
      • Zarasim
      • commented on "#1 Sequences: Pure Even Digit Perfect Squares (P.E.D.P.S)" kata
      • 3 years ago

      This comment is hidden because it contains spoiler information about the solution

    • Custom User Avatar
      • depial
      • commented on "#1 Sequences: Pure Even Digit Perfect Squares (P.E.D.P.S)" kata
      • 3 years ago

      I can't see your current algorithms, but if you are taking n = b-a square roots, then, yes, there is a faster way. In that case, if you think more carefully about what is needed to solve the problem, you can probably find a simple way to speed things up without changing your algo very much.

    • Custom User Avatar
      • Zarasim
      • commented on "#1 Sequences: Pure Even Digit Perfect Squares (P.E.D.P.S)" kata
      • 3 years ago

      I am using math.sqrt to check for perfect squares. Is there a less time consuming approach?
      I have passed all the tests but not the attempt session.

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