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brander Avatar
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Member Since:Jan 2017
Last Seen:Feb 2025
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  • Replies (9)
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  • Custom User Avatar
    • solitude
    • commented on "A Gift Well Spent" kata
    • 6 years ago

    Now fixed.

  • Custom User Avatar
    • dulot
    • commented on "First Variation on Caesar Cipher" kata
    • 8 years ago

    You should read again the description!

  • Custom User Avatar
    • jungerstein
    • commented on "First Variation on Caesar Cipher" kata
    • 8 years ago

    But, thence, 16 would be [4, 3, 3, 3, 3] instead of the given [4, 4, 4, 4, 0].

    Also, I cannot derive the split [4, 4, 4, 4, 0] given the rules. It breaks the rule 'the fifth part has the longest length'.

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    • deadwater
    • commented on "First Variation on Caesar Cipher" kata
    • 8 years ago

    I think 6 would be [2,1,1,1,1] and 7 would be [2,2,1,1,1] and 11 would be [3,2,2,2,2] mainly driven by the restriction that the fifth portion be as long as possible but less than or equal to the other 4.

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    • g964
    • commented on "Second Variation on Caesar Cipher" haskell solution
    • 8 years ago

    Maybe I thought I could use negative numbers...

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    • PG1
    • commented on "Holiday I - Temperature in Bali" kata
    • 8 years ago

    Have you tried logging the inputs to the console so you can see them?

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    • pszczolas
    • commented on "First Variation on Caesar Cipher" kata
    • 8 years ago

    Same question abuot length equals 7 or 11

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    • Bodigrim
    • commented on "Last digit of a huge number" kata
    • 8 years ago

    Feel free to contribute such test case :)

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    • suic
    • commented on "1's, 0's and wildcards" haskell solution
    • 8 years ago

    Thanks :)

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