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gegonzalezvs.gaston-areco-tq

Find maximum number that can be formed using digits of a given number

Code
Diff
  • import java.util.Arrays;

public class MaxNumber {
    public static long print(long number) {
        long result = 0;

        String digitsString = String.valueOf(number);
        long digits[] = new long[digitsString.length()];

        for (int i = 0; i < digitsString.length(); i++){
          long digit = Character.getNumericValue(digitsString.charAt(i));
          digits[i] = digit;
        }

        Arrays.sort(digits);

        for (int i = 0; i < digits.length; i ++){
          result = result + digits[i] * (long)(Math.pow(10, i));
        }
        return result;    
    }
}
    • import java.util.Arrays;
    • public class MaxNumber {
    • public static long print(long number) {
    • return number
    • long result = 0;
    • String digitsString = String.valueOf(number);
    • long digits[] = new long[digitsString.length()];
    • for (int i = 0; i < digitsString.length(); i++){
    • long digit = Character.getNumericValue(digitsString.charAt(i));
    • digits[i] = digit;
    • }
    • Arrays.sort(digits);
    • for (int i = 0; i < digits.length; i ++){
    • result = result + digits[i] * (long)(Math.pow(10, i));
    • }
    • return result;
    • }
    • }