You used my previous solution ;)

Yes, the function even_or_odd returns the string "Even" if the input n is even and "Odd" if the input n is odd

alright i'm sorry

Hi Sara,

I would suggest you to try to run the code. The module operator (%) return the reminder in the division between the first and the second number. 6 divided by 2 is 3 with 0 as remainder, so in this code would be select the first item in the tuple, "Even", that is correct. Your version is easier to understand and more suitable for python, but the code written by graf_da still works.

if i enter "6", your code will throw KeyError because 6 % 2 == 2. so i'd rather do

def even_or_odd(n: int) -> str:
  return 'Even' if n % 2 == 0 else 'Odd

We have a fun time ¯\(ツ)/¯

what are you guys doin here?
:)