Hi,

The description is still incorrect:

Show that this process terminates.

That's not at all what is asked for. The expected answer is find the minimum amount of flips needed to terminate the porcess.

Ruby 3.0 should be enabled, see this to learn how to do it

How is the number of digits determined? If 45[10] = 101101[2] has 6 digits, then 0[10] = 0[2] has digits, following the same logic (all numbers from 0 to 0 can be represented with 0 bits). If 0 has 1 digit, then why should 45 be 101101 and not 0101101 for example?

Nice idea, but testing is ATM quite insuffucient indeed.

I haven't thought it through, but are there edge cases where negative numbers come into play? If so, you want those as fixed tests. Or you want to specify a more restricted input domain.

(Bitwise operators operate on 32-bit integers but JS internally represents up to 53-bit integers.)

But first, really, random tests! :]