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Why isn't the answer (523681, 999999)? That would produce the desired repeating decimal.
Why is the reference solution using floating point math when an exact integer solution is possible?
Fix the random tests to invalidate this solution:
https://www.codewars.com/kata/reviews/66bce4158fed1ddb86d680b7/groups/66bcef7d8fed1ddb86d68228
This issue was corrected for the fixed tests but random tests still aren't testing anything.
For this "solution":
I got this result:
Also https://www.codewars.com/kata/reviews/66bce4158fed1ddb86d680b7/groups/66bcea6e8fed1ddb86d6818b
The tests aren't testing anything.
I made a mistake in this solution but still passed: https://www.codewars.com/kata/reviews/66bce4158fed1ddb86d680b7/groups/66bce9654a6f487c43156bc3
Some of the edge cases may need explanation.
When the cathetus is equal to the hypotenuse, that could mean that the "other side" of the right triangles is zero, so the four right triangles are all zero-area. Then the inner square is equal in area to hypotenuse ** 2.
But the edge case tests expect 0 for the result. Why?
Still see the following in the desc:
The question remains though. Which line or line segment do you mean by "cathetus"? It could be the shorter leg or the longer leg or maybe it doesn't matter. That is unclear.
Nothing in the diagram is marked.
So which length in the diagram is b?
As a concrete example, the reason why rounding to 2 decimal places is not a panacea is there is one test where one of the values is -5.055
Depending on the order in which you do the calculations, you may get -5.05499999 or -5.055000001, which round to different results in two decimal places.
Consider this:
5 * 16 = 80 images can fit into the area.
Why is 77 the expected answer?
Total driving time is over 10 hours. Why does it expect the result to be true?
After trying out a few things, I think the problem is the kata description has odd and even swapped in the non-palindrome cases.
37 is an odd and non-palindromic number. Why does the test expect 110 instead of 73?
There doesn't seem to be a test for the color argument.
My solution was able to pass even though it always set the cells to '⬛'
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