To enhance fastness, it would be better to convert the String to StringBuilder, do the replaces like we did with String, and then convert the SB back to String. But it would still remain in O(n), thus it may not be worth the effort, but is nice to know.
Kata says:
Cool
Wow. It's cool
Nothing. Regular string concatenation faster that String#format. You can find in google performance of regular concatenation and String#format.
In case when sum of all numbers < k your code will be execute infinity
If the passed array has no missed letters, your solution will end with ArrayIndexOutOfBoundsException.
For instance, ['a', 'b', 'c', 'd', 'e'] -> ' '.
bad performance
errr, possibly, but if you go for readability...?
Yes, it short solution, but performance of String#format is very bad.
I'm sorry.
Thank you.
Please, use spoiler flag next time.
This comment is hidden because it contains spoiler information about the solution
O.o
Short but not effective
To enhance fastness, it would be better to convert the String to StringBuilder, do the replaces like we did with String, and then convert the SB back to String. But it would still remain in O(n), thus it may not be worth the effort, but is nice to know.
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